Quidditch, Number of Games, & Who Attends

[Steve <bboy_mn@yahoo.com>]

No: HPFGUIDX 50637

--- In HPforGrownups at yahoogroups.com, "christi0469 <christi0469 at h...>"
<christi0469 at h...> wrote:
> bboy wrote,
> 
> (material snipped)
> 
> > So, I wonder if they used a process of elimination. The two 
> > weakest teams from the year before, play the two strongest 
> > teams. Winners of those two games play each other for the final 
> > championship. Total=  3 games. ..edited..
> > (more snipped material)
> 
> my reply- (christi)
> 
> I think the events of PoA make this scenario impossible. Gryffindor 
> plays Hufflepuff, then Ravenclaw, then Slytherin. In a three game 
> season Gryffindor would be excluded from at least one of the games. 
>
> ...edited...
> 
> If the Cup is awarded on the basis of points, then all teams should 
> be allowed to play all three other houses. 
> 
> ..edited...
> 
> Christi

bboy_mn:

I don't claim to have a good memory, in fact, it is notoriously bad.
But after I posted my original question, I seemed to remember
Gryffindor playing Slytherin twice is one season, but I'm not sure
what book that would be in (maybe PoA; that seems to be a very
Quidditch book). 

Is this just a dream I had one night, or do other people remember this?

If that were true, and we assume a standard play format where every
team plays every team at least once (6 games total), then how did they
play Slytherin twice. If I have to invent a solution it would be, 6
games for the season, then a play-off of the two top teams for the
final championship. It makes sense, but that's not the impression I
got from reading the book.

In the end the answer is always going to be 'it's fiction', but it is
intriguing.

Just some thoughts.

bboy_mn